Question

The sum of three numbers is 71. The third number is 2 times the first. The second number is 5 less than the first. What are the numbers?

Answer 1

19, 14, 38

Explanation:

Let x, y, and z be each number respectively:

`x+y+z=71\\z=2x\\y=x-5\\\\x+y+z=71\\x+(x-5)+2x=71\\2x-5+2x=71\\4x-5=71\\4x=76\\x=19\\\\y=x-5\\y=19-5\\y=14\\\\z=2x\\z=2(19)\\z=38`

Therefore, the three numbers are 19, 14, and 38.