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Find the equation of the tangent line to the graph of f(x) = √x+81 at the point (0,9).

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Answer:

dy/dx = 1/2 x ^(-1/2)

gradient for point (0,9) = 1/6

y-0 = 1/6 (x-9)

y = 1/6 (x-9)

Find the equation of the tangent line to the graph of f(x) = √x+81 at the point (0,9).-example-1
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