Question

Pls help only got a little time left

Answer 1

EF = 0.6

Explanation:

Tangent CD touches the circle at D

⇒ CD⊥ DO

⇒ ∠CDO = ∠CDF = 90°

⇒ CDF is a right angled triangle

⇒ CD² + DF² = CF²

⇒ 2.4² + 1.8² = CF²

⇒ CF² = 9

⇒ CF = √9

⇒ CF = 3

Also,

⇒ CF = CE + EF

⇒ CE + EF = 3 -----------eq(1)

The tangents to a circle from an external point are equal lenght

Here C is the external point

⇒ CD = CE

⇒ CE = 2.4

sub in eq(1),

2.4 + EF = 3

⇒ EF = 3 - 2.4

⇒ EF = 0.6