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Determine the value of k such that (x-4) is a factor of the following polynomial.

f(x)=x³ 2x²-11x +k

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Answer:

Explanation:

To determine the value of k such that (x-4) is a factor of the polynomial f(x) = x³ + 2x² - 11x + k, we need to find the remainder when f(x) is divided by (x-4). If the remainder is zero, then (x-4) is a factor of the polynomial.

Using polynomial long division, we divide f(x) by (x-4):

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x² + 6x + 5

____________________

x - 4 | x³ + 2x² - 11x + k

- (x³ - 4x²)

___________

6x² - 11x

- (6x² - 24x)

___________

13x + k

- (13x - 52)

___________

k + 52

The remainder is k + 52. For (x-4) to be a factor of the polynomial, the remainder should be zero. Therefore, we have the equation k + 52 = 0.

Solving for k, we get:

k = -52

So, the value of k that makes (x-4) a factor of the polynomial is k = -52.

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