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Find the sum of the first 37 terms in the sequence 14,23,32,41

User Samie
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1 Answer

4 votes

Answer:

6512

Explanation:

This is an arithmetic sequence. Each term is obtained by adding 9 to the previous term.

First term = a = 14

Common difference = d = second term - first term

= 23 - 14

d = 9

number of terms = n = 37


\boxed{\bf S_n = (n)/(2)(2a + (n-1)d}\\\\\text{\bf $ \bf S_n$ is the sum of first n terms.} \\\\


\sf S_(37)= (37)/(2)(2*14 + (37-1)*9)\\\\\\~~~~~ = (37)/(2)(28+36*9)\\\\~~~~~=(37)/(2)*(28+324)\\\\\\~~~~~= (37)/(2)*352\\\\~~~~~= 37 * 176\\\\S_(37)=6512

User Bbusdriver
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