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A motorcycle initially travelling at 15.0 m/s comes to rest in 5.0 s. What is its deceleration and how

far does it travel during deceleration?

User Zied Feki
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1 Answer

16 votes
16 votes

The deceleration of the motorcycle is -3.0 m/s^2 and it travels 75.0 m during deceleration.

To find the deceleration of the motorcycle, we can use the formula:

deceleration = (final velocity - initial velocity) / time

Plugging in the given values, we get:

deceleration = (0 m/s - 15.0 m/s) / 5.0 s = -3.0 m/s^2

To find the distance the motorcycle travels during deceleration, we can use the formula:

distance = (initial velocity * time) + (1/2 * deceleration * time^2)

Plugging in the given values, we get:

distance = (15.0 m/s * 5.0 s) + (1/2 * -3.0 m/s^2 * 5.0 s^2) = 75.0 m

So the deceleration of the motorcycle is -3.0 m/s^2 and it travels 75.0 m during deceleration.

User LodeRunner
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