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A committee of two persons is selected from two men and two women. What is the probability that the committee will have

(i) no man?

(ii) one man?

(iii) two men?

1 Answer

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Step-by-step explanation:

To determine the probabilities, we need to calculate the total number of possible committees and the number of committees that satisfy each condition. Let's calculate the probabilities step by step:

(i) Probability of no man:

To form a committee with no man, we need to choose 2 women from the available 2 women. This can be calculated as follows:

Total number of possible committees = C(4, 2) = 6

Number of committees with no man = C(2, 2) = 1

Therefore, the probability of having no man on the committee is 1 out of 6, which can be expressed as 1/6.

(ii) Probability of one man:

To form a committee with one man, we can choose 1 man from the available 2 men and 1 woman from the available 2 women. The calculation is as follows:

Total number of possible committees = C(4, 2) = 6

Number of committees with one man = C(2, 1) * C(2, 1) = 4

Therefore, the probability of having one man on the committee is 4 out of 6, which simplifies to 2/3.

(iii) Probability of two men:

To form a committee with two men, we need to choose 2 men from the available 2 men and no women. The calculation is as follows:

Total number of possible committees = C(4, 2) = 6

Number of committees with two men = C(2, 2) = 1

Therefore, the probability of having two men on the committee is 1 out of 6, which can be expressed as 1/6.

In summary:

(i) Probability of no man = 1/6

(ii) Probability of one man = 2/3

(iii) Probability of two men = 1/6

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