Question

The circle below is centered at the point (4, 1) and has a radius of length 2.

What is its equation?
10
A. (x-4)² + (v-1)2 = 4
B. (x-1)2 + (v-4)2 = 4
C. (x + 1)2 + (v-4)² =
22
D. (x+4)2 + (y- 1)²2 = 4

Answer 1

A

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (4, 1 ) and r = 2 , then

(x - 4)² + (y - 1)² = 2² , that is

(x - 4)² + (y - 1)² = 4 ← equation of circle