Question

What is the value of f(−6) when f(x)=x2+8x+1

Answer 1

The answer is:

f(-6) = -11

Explanation:

Plug in -6 for x:

`\sf{f(x)=x^2+8x+1}`

`\sf{f(-6)=(-6)^2+8(-6)+1}`

Simplify this:

`\sf{f(-6)=36-48+1}`

`\sf{f(-6)=-12+1}`

`\sf{f(-6)=-11}`

∴ f(-6) = -11

Answer 2

-11

Explanation:

Notice how

`f(x)=x^(2) +8x+1`

So when we have

`f(-6)=(-6)^(2) +8(-6)+1= 36-48+1=-11`