Answer:
60.45 grams of copper
Step-by-step explanation:
To determine the amount of copper (Cu) produced from a given mass of chromium (Cr), we need to use the balanced chemical equation for the reaction between chromium and copper sulfate:
Cr + CuSO4 → Cu + Cr2(SO4)3
From the equation, we can see that the stoichiometric ratio between chromium and copper is 1:1. This means that for every 1 mole of chromium reacted, 1 mole of copper is produced.
First, we need to calculate the number of moles of chromium:
Molar mass of chromium (Cr) = 52.00 g/mol
Mass of chromium (Cr) = 49.48 g
Number of moles of chromium (Cr) = Mass / Molar mass
Number of moles of chromium (Cr) = 49.48 g / 52.00 g/mol
Number of moles of chromium (Cr) ≈ 0.951 mol
Since the stoichiometric ratio between chromium and copper is 1:1, the number of moles of copper produced will also be 0.951 mol.
Next, we can calculate the mass of copper (Cu) produced:
Molar mass of copper (Cu) = 63.55 g/mol
Mass of copper (Cu) = Number of moles * Molar mass
Mass of copper (Cu) = 0.951 mol * 63.55 g/mol
Mass of copper (Cu) ≈ 60.45 g
Therefore, approximately 60.45 grams of copper would be produced from 49.48 grams of chromium.