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How many grams of copper would be produced from 49.48 g of chromium? cr cuso4 → cu cr2(so4)3

User Coryrwest
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1 Answer

4 votes

Answer:

60.45 grams of copper

Step-by-step explanation:

To determine the amount of copper (Cu) produced from a given mass of chromium (Cr), we need to use the balanced chemical equation for the reaction between chromium and copper sulfate:

Cr + CuSO4 → Cu + Cr2(SO4)3

From the equation, we can see that the stoichiometric ratio between chromium and copper is 1:1. This means that for every 1 mole of chromium reacted, 1 mole of copper is produced.

First, we need to calculate the number of moles of chromium:

Molar mass of chromium (Cr) = 52.00 g/mol

Mass of chromium (Cr) = 49.48 g

Number of moles of chromium (Cr) = Mass / Molar mass

Number of moles of chromium (Cr) = 49.48 g / 52.00 g/mol

Number of moles of chromium (Cr) ≈ 0.951 mol

Since the stoichiometric ratio between chromium and copper is 1:1, the number of moles of copper produced will also be 0.951 mol.

Next, we can calculate the mass of copper (Cu) produced:

Molar mass of copper (Cu) = 63.55 g/mol

Mass of copper (Cu) = Number of moles * Molar mass

Mass of copper (Cu) = 0.951 mol * 63.55 g/mol

Mass of copper (Cu) ≈ 60.45 g

Therefore, approximately 60.45 grams of copper would be produced from 49.48 grams of chromium.

User Jarondl
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