Question

What is the resistance of a 60 Watt light bulb that allows 500 mA to flow when 120 V is applied to it?

Answer 1

The resistance of the 60 Watt light bulb is 240 ohms.

Step-by-step explanation:

To calculate the resistance of the light bulb, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). In this case, we are given the voltage (V = 120 V) and the current (I = 500 mA = 0.5 A). However, we first need to convert the power (60 Watts) into current using the equation P = IV.

P = IV

60 W = (0.5 A) * V

Now, we can rearrange the equation to solve for voltage:

V = (60 W) / (0.5 A)

V = 120 V

Now, we have the voltage (V = 120 V) and the current (I = 0.5 A). We can substitute these values into Ohm's Law to calculate the resistance:

R = V / I

R = 120 V / 0.5 A

R = 240 Ω