Question

points A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3+65.00f, what is the last deflection angle (degrees) (l.e. the angle subtended by the roadway between the tast full station and the PT)? ∫1ast​=Δ/2=110/2=55 1 points

Answer 1

To calculate the last deflection angle (Δ/2) for the given horizontal curve, we can use the formula:

Last Deflection Angle (Δ/2) = Total Deflection Angle / 2

In this case, the total deflection angle is given as 110 degrees. Plugging it into the formula, we get:

Last Deflection Angle (Δ/2) = 110 / 2 = 55 degrees

Therefore, the last deflection angle, which is the angle subtended by the roadway between the tangent full station (TFS) and the point of tangency (PT), is 55 degrees.