Question

How much force is required to make a 20.0 kg piece of steel steadily change its velocity from 0.00 km/h to 20.0 km/h in period of 0.566 s ? (Hint: determine the acceleration first)

11.8 N
11.8kN
0.196kN
196kN
​

Answer 1

The answer is 0.196KN

Step-by-step explanation:

`m = 20kg`

`v = 20kmh {r}^( - 1)`

`u = 0kmh {r}^( - 1)`

convert km/hr to m/s

`v= (20 * 1000)/(3600) m {s}^( - 1)`

v=5.56m/s

`u = (0 * 1000)/(3600) m {s}^( - 1)`

u=0m/s

`a = (v - u)/(t)`

`a = (5.56 - 0)/(0.566)`

`a = (5.56)/(0.566)`

a=9.82

`f = ma`

`f = 20 * 9.82`

`f = 196.4`

F=196.4N

F=0.1964KN or 0.196KN