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What is the equation of the line that passes through the point (3, 5) and has a slope of 1?

User Alison S
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Explanation:

in what form do we need the equation ?

slope-intercept ?

that would be

y = ax + b

with "a" being the slope and "b" being the y-intercept (the y-value when x = 0).

in any case, since we have the slope and a point, we can start with the point-slope form :

y - yp = a(x - xp)

"a" is again the slope, and (xp, yp) is the given point.

so,

y - 5 = 1×(x - 3) = x - 3

adding 5 to both sides gives us

y = x + 2

and that is our desired equation in slope-intercept form.

User Fuzzyma
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