Question

V=IR I=6.7 correct to 1 decimal place R=11.81 correct to 2 decimal places Work out the upper bound for V. Give your answer to 2 decimal places.

Answer 1

To find the upper bound for V, we need to consider the maximum possible values for I and R within their given tolerances.

The maximum value for I, correct to 1 decimal place, would be 6.8 (6.7 + 0.1).

The maximum value for R, correct to 2 decimal places, would be 11.82 (11.81 + 0.01).

Now we can calculate the upper bound for V using the formula V = IR:

V = 6.8 * 11.82 = 80.376

Rounding this value to 2 decimal places, the upper bound for V is 80.24.

Explanation:

Rounding this value to 2 decimal places, the upper bound for V is 80.24