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Which equation is equivalent to: G=H−T×S ?T=(H−G)/S, S=(G−H)/T, H=(G−T)/S​

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2 votes

Answer:

Explanation:

The equations you provided, T=(H−G)/S, S=(G−H)/T, and H=(G−T)/S, are equivalent to the equation G=H−T×S. These equations describe a system in which the variables G, H, S, and T are related in a certain way.

T=(H−G)/S means that T is equal to the ratio of (H−G) divided by S. Similarly, S=(G−H)/T means that S is equal to the ratio of (H−G) divided by T. And H=(G−T)/S means that H is equal to the ratio of (G−T) divided by S. These equations can be used to solve for the values of T, S, and H in terms of G, or vice versa, depending on the values of the variables that are given.

To solve for G in terms of T, S, and H, we can start by rewriting the equations in terms of G:

G=(H−T)/S or S=(G−H)/T or H=(G−T)/S

Next, we eliminate G from the equations by multiplying the second and third equations:

S=(G−H)/T × (T−H)/S = (G−H)(T−H)/S^2

Simplifying, we get:

(G−H)T = S^2(T−H)

Solving for G, we get:

G=(S^2(T−H)+HT)/(S(H−T))​

To solve for H in terms of T, S, and G, we can use the same approach:

H=(G−T)/S or S=(G−H)/T or T=(G−H)/S

Next, we eliminate G by multiplying the first and third equations:

H=(G−T)/S × (T−H)/S = (G−T)(T−H)/S^2

Simplifying, we get:

(G−H)T = H^2(S^2−T^2)

Solving for H, we get:

H=(S^2(G−T) ± sqrt(S^4(G−T)^

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