Answer:
in explanation
Explanation:
LHS =1+sinAcot2A(secA−1)
=sin2A(1+sinA)×cosAcos2A(1−cosA)
=sin2A(1+sinA)cosA(1−cosA)×(1−sinA)(1+cosA)(1−sinA)×(1+cosA)
=(1+cosA)(1−sinA)×cosA1
=cosA×cosA(1+secA)1×(1−sinA)
=sec2A(1+secA1−sinA)
1.6m questions
2.0m answers