Answer:
The point (-5, 0) lies on neither of the two lines in the system of equaitons
Explanation:
We can substitute (-5, 0) into both equations by plugging in -5 for x and 0 for y.
Substituting (-5, 0) for x and y in 4x + 4y = 8:
4(-5) + 4(0) = -8
-20 ≠ -8
Thus, (-5, 0) does not lie on 4x + 4y = -8
Substituting (-5, 0) for x and y in 2x + 5y = -1
2(-5) + 5(0) = -1
-10 ≠ -1
Thus, (-5, 0) does not lie on 2x + 5y = -1 either.
Therefore, the point (-5, 0) lies on neither of the two lines.