Question

At what separation is the electrostatic force between a +11.2μC point charge and a + 29.1 μC point charge cqual in magnitude to 1.57 N ?

Answer 1

To find the separation at which the electrostatic force between two point charges equals 1.57 N, we can use Coulomb's Law and solve for the separation distance.

Step-by-step explanation:

To find the separation at which the electrostatic force between two point charges equals 1.57 N, we can use Coulomb's Law:

F = k(q1*q2)/r^2

Where:

• F is the magnitude of the electrostatic force
• k is the electrostatic constant (9.0x10^9 N*m^2/C^2)
• q1 and q2 are the magnitudes of the charges (+11.2 μC and +29.1 μC in this case)
• r is the separation between the charges

Simplifying the equation and solving for r:

r = sqrt(k(q1*q2)/F)

Plugging in the values, we have:

r = sqrt((9.0x10^9 N*m^2/C^2)(11.2x10^-6 C)(29.1x10^-6 C)/(1.57 N))

r ≈ 0.014 m

Therefore, the separation at which the electrostatic force equals 1.57 N is approximately 0.014 meters.