Answer:
118 students
Explanation:
To find the number of students who took the exam, we can use the concept of z-scores and the properties of a standard normal distribution.
Given:
Mean (μ) = 64
Standard Deviation (σ) = 10
We have the following information:
Number of students who scored between 73 and 86 = 20
To calculate the z-score, we use the formula:
z = (x - μ) / σ
For the lower limit of 73:
z1 = (73 - 64) / 10 = 0.9
For the upper limit of 86:
z2 = (86 - 64) / 10 = 2.2
Now, we can look up the z-scores in the standard normal distribution table to find the corresponding cumulative probabilities.
From the z-score table, the cumulative probability for z = 0.9 is approximately 0.8159, and for z = 2.2, it is approximately 0.9857.
To find the number of students who scored between 73 and 86, we subtract the cumulative probabilities:
Number of students = (0.9857 - 0.8159) * N
= 0.1698 * N
Given that this is equal to 20 students, we can set up an equation:
0.1698 * N = 20
Solving for N:
N = 20 / 0.1698
N ≈ 117.74
Since the number of students must be a whole number, we can round it up to the nearest integer:
N ≈ 118
Therefore, approximately 118 students took the English 10 provincial exam.