Question

Can someone help me please

Answer 1

The hypotenuse is
`8√(3)` and the other missing side is 12

Explanation:

We use the 60 degree angle and side length 4sqrt(3) to find the hypotenuse using,

H = Hypotenuse

Y = The other side that we need to find

cos(a) = Adjacent/H

H = Adjacent/cos(a)

`Adjacent = 4√(3) \\a = 60\\H = 4√(3) /cos(60)\\H = 8√(3)`

Now, finding the other side,

Using

tan(a) = Y/Adjacent

Y = (Adjacent)(tan(a)

`adjacent = 4√(3) \\a = 60\\Y = (4√(3) )(tan(60))\\Y = 12`

hence the hypotenuse is 8sqrt(3) and the other side is 12