Question

Write the equation of a line with a slope of -4 passing through the point (-3, -1). Write the equation in slope-intercept form.​

Answer 1

`y=-4x-13`

Explanation:

`y-y_1=m(x-x_1)\\y-(-1)=-4(x-(-3))\\y+1=-4(x+3)\\y+1=-4x-12\\y=-4x-13`

Answer 2

The answer is:

y = -4x - 13

Work/explanation:

I will begin by writing the line's equation in point slope:

`\rm{y-y_1=m(x-x_1)}`

Where m = slope, (x₁,y₁) is a point.

Plug in the data:

`\begin{gathered}\sf{y-y_1=m(x-x_1)}\\\sf{y-(-1)=-4(x-(-3)}\\\sf{y+1=-4(x+3)}\\\sf{y+1=-4x-12}\\\sf{y=-4x-12-1}\\\sf{y=-4x-13}\end{gathered}`

Hence, the answer is y = -4x - 13.