Find all solutions to the equation 6x^3+30x^2+45x+27=0

Question

asked Aug 11, 2024 12.1k views

2 Answers

The Vee · Answer 1 · 2024-08-17T04:21:30+0000

Answer:

all zeroes are

x = -3, {-2+(square root of 22)}/ 2

or {-2-(square root of 22)}/ 2

Explanation:

6x^3+30x^2+45x+27= 0

divide both sides with 3

2x^3+10x^2+15x+9=0

(x+2)(2x^2+4x+3)=0

let 2x^2+4x+3 =0

then x= {-2+(square root of 22)}/ 2

or x = {-2-(square root of 22)}/ 2

similarly if x+3=0

then x = -3