Given,Temperature of the gas, T = 290 KPressure of the gas, P = 105 kPaDiameter of the gas molecules, d = 30 × 10^-19 mFirst we have to find the volume of one molecule of the gas. It can be given as:V = (4/3) × π(d/2)^3V = (4/3) × π(15 × 10^-19 m)^3V = 1.41 × 10^-57 m^3Now, we have to find the fraction of the volume occupied by the gas molecules. It can be given as:Fraction of the volume occupied by the gas molecules = (Volume of the gas molecules × Number of gas molecules) / Volume of the containerNumber of gas molecules can be calculated using the ideal gas equation as:n = PV / RTn = (105 × 10^3 Pa × 1 m^3) / (8.31 J/K mol × 290 K)≈ 0.00412 molNumber of gas molecules = 0.00412 × 6.022 × 10^23 = 2.48 × 10^21Fraction of the volume occupied by the gas molecules = (V × n) / VcontainerFraction of the volume occupied by the gas molecules = n = 2.48 × 10^21 ≈ 2.5 × 10^21 (approx)Therefore, the fraction of the volume found in part A that is occupied by the molecules is 2.5 × 10^21.