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A decision problem has the following three constraints: \( 5 X+60 Y

User Zied Feki
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Explanation:

The given decision problem can be represented as:5X + 60Y ≤ 300X + 4Y ≥ 7X + Y ≤ 10To plot the feasible region for this problem, we can use the intercepts method:Let's consider the equation 5X + 60Y = 300:At X = 0, 5(0) + 60Y = 300, Y = 5At Y = 0, 5X + 60(0) = 300, X = 60The point of intersection is (0, 5) and (60, 0).Let's consider the equation X + 4Y = 7:At X = 0, 4Y = 7, Y = 1.75At Y = 0, X = 7The point of intersection is (0, 1.75) and (7, 0).Let's consider the equation X + Y = 10:At X = 0, Y = 10At Y = 0, X = 10The point of intersection is (0, 10) and (10, 0).Therefore, the feasible region is the triangle formed by the points (0, 5), (7, 1.75), and (5, 5).

User Jonathan Michalik
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