Question: Given a list of integers, return a list where each integer is multiplied by 2. doubling([1, 2, 3]) → [2, 4, 6] doubling([6, 8, 6, 8, -1]) → [12, 16, 12, 16, -2] doubling([]) → []Main Answer:Here is the main answer of your question:One way to return a list where each integer is multiplied by 2 is by using list comprehension. Here is the Python code for the doubling function:def doubling(nums): return [num * 2 for num in nums]The explanation: The doubling function takes a list of integers as input and uses list comprehension to create a new list where each integer is multiplied by 2. The list comprehension expression `[num * 2 for num in nums]` iterates over each element `num` in the input list `nums` and multiplies it by 2. The resulting list of doubled integers is returned as output.Example usage of the doubling function:>>> doubling([1, 2, 3]) [2, 4, 6]>>> doubling([6, 8, 6, 8, -1]) [12, 16, 12, 16, -2]>>> doubling([]) []