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Suppose that the resistance between the walls of a biological cell is \( 4.3 \times 10^{9} \Omega \). (a) What is the current when the potential difference between the walls is \( 81 \mathrm{mV} \) ?

User Jamal
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To calculate the current using Ohm's Law, we can use the formula:

\[ I = \frac{V}{R} \]

Where:

- I is the current,

- V is the potential difference (voltage),

- R is the resistance.

In this case, the potential difference (V) is given as 81 mV, which we can convert to volts by dividing by 1000:

\[ V = 81 \, \mathrm{mV} = 81 \times 10^{-3} \, \mathrm{V} \]

The resistance (R) is given as \( 4.3 \times 10^9 \, \Omega \).

Now we can substitute these values into the formula to calculate the current (I):

\[ I = \frac{81 \times 10^{-3} \, \mathrm{V}}{4.3 \times 10^9 \, \Omega} \]

To simplify the calculation, we can divide the numerator and denominator by \( 10^{-3} \):

\[ I = \frac{81}{4.3 \times 10^9} \, \mathrm{A} \]

Thus, the current when the potential difference between the walls is 81 mV is approximately \( \frac{81}{4.3 \times 10^9} \) Amperes.

User Sam Firke
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