Final Answer:
(a) The x-component of the net momentum of A and C is 16 kg m/s, and the y-component is 0 kg m/s.
(b) The x-component of the net momentum of B and C is -24 kg m/s, and the y-component is -8 kg m/s.
(c) The x-component of the net momentum of all three objects is -8 kg m/s, and the y-component is -8 kg m/s.
Step-by-step explanation:
When considering the x and y components of momentum for the pairs of particles:
(a) For A and C, the x-components add up as both have positive momentum in the x-direction (8 kg m/s + 8 kg m/s = 16 kg m/s), while in the y-direction, they both have zero momentum, resulting in 0 kg m/s as the net y-component.
(b) Considering B and C, their x-components result in a subtraction (0 kg m/s - 24 kg m/s = -24 kg m/s) due to B's negative momentum in the x-direction. In the y-direction, C's momentum (-8 kg m/s) subtracts from B's momentum (-8 kg m/s), yielding a net y-component of -8 kg m/s.
(c) When accounting for all three objects, their x-components combine (16 kg m/s - 24 kg m/s = -8 kg m/s) and the y-components add up (-8 kg m/s + (-8 kg m/s) = -16 kg m/s), resulting in -8 kg m/s for both x and y components of the net momentum.
This analysis demonstrates how combining the momenta of different pairs of objects in the x and y directions provides the net momentum of the specified groups.
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