The student earned grades of A,B,B,C, and D with corresponding credit hours of 3, 3, 3, 4 and 2. The quality points assigned to the grades are:
A = 4, B = 3, C = 2, D = 1, F = 0.
We need to calculate the student's GPA using the following formula:
GPA = (total quality points earned) / (total credit hours) Total credit hours = 3+3+3+4+2 = 15 Quality points earned = (4 × 3) + (3 × 3) + (3 × 3) + (2 × 2) + (1 × 2) = 4(3)+3(3)+3(3)+2(2)+1(2) = 12+9+9+4+2 = 36.
Therefore, the student's GPA = (total quality points earned) / (total credit hours) = 36/15 ≈ 2.40. The student's GPA is 2.40 which is less than the required GPA of 3.00 for the Dean's list.
So, the student did not make the Dean's list.