Question

A horizontal rectangular surface has dimensions Part A 3.10 cm by 3.15 cm and is in a uniform magnetic field that is directed at an angle of 28.5°above the What must the magnitude of the magnetic field be to produce a flux of 3.60×10^−4

Wb through horizontal. the surface? Express your answer with the appropriate units.

Answer 1

The magnitude of the magnetic field must be 29.0 nT

This is found using the equation

B=uNI/cosQ
Where B is the magnetic field strength, u is the magnetic permeability of free space, N is the unit normal vector pointing out of the surface, and Q is the angle between the unit normal vector and the magnetic field.

In this case the angle between the unit normal vector and the magnetic field is 90 degrees - 28.5 degrees = 61.5 degrees