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Instructions are as given:

Find the degree, the leading term, the leading coefficient, the constant term and the end behavior of the given polynomial.

p(t)=-t²(3 - 5t) (t²+ t + 4)

User Majico
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1 Answer

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The given polynomial is:

p(t) = -t²(3 - 5t)(t² + t + 4)

To find the degree of the polynomial, we need to determine the highest power of t in the expression. This is given by:

degree = 2 + 1 + 2 = 5

So the degree of the polynomial is 5.

The leading term of the polynomial is the term with the highest power of t. This is given by:

leading term = -t² * 5t² = -5t^4

So the leading term of the polynomial is -5t^4.

The leading coefficient of the polynomial is the coefficient of the leading term. This is given by:

leading coefficient = -5

So the leading coefficient of the polynomial is -5.

The constant term of the polynomial is the term that does not contain any powers of t. This is given by:

constant term = -t²(3)(4) = -12t²

So the constant term of the polynomial is -12t^2.

To find the end behavior of the polynomial, we need to determine what happens to the value of the polynomial as t approaches positive or negative infinity. Since the degree of the polynomial is odd, we know that the end behavior will be opposite for t approaching positive or negative infinity. We can use the leading term to determine the end behavior:

- as t approaches positive infinity, the leading term approaches negative infinity, so the end behavior is p(t) → -∞ as t → ∞

- as t approaches negative infinity, the leading term approaches positive infinity, so the end behavior is p(t) → ∞ as t → -∞

So the end behavior of the polynomial is:

- p(t) → -∞ as t → ∞

- p(t) → ∞ as t → -∞

User Nicko Po
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