32.0k views
4 votes
Given: m∠3 = (3x − 20)° and m∠7 = (2x + 30)°

What value of x will prove that the horizontal lines are parallel?

Given: m∠3 = (3x − 20)° and m∠7 = (2x + 30)° What value of x will prove that the horizontal-example-1
User Mornindew
by
7.9k points

1 Answer

6 votes

Answer:

x = 50

Explanation:

  • The left side of the triangle is a traversal as it separates the two parallel lines.
  • When two lines are parallel and cut by a traversal, corresponding angles are made.
  • These types of angles are formed in the matching corners or corresponding corners with the transversal.
  • They are always congruent.
  • Thus, in order for the two lines to be parallel, m∠3 must equal m∠7.

Thus, we can find the value of x proving the horizontal lines are parallel by setting the two expressions representing the measures of angles 3 and 7 equal to each other:

(3x - 20 = 2x + 30) + 20

(3x = 2x + 50) - 2x

x = 50

Thus, 50 is the value of x proving that the horizontal lines are parallel.

User Uzul
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories