Question

Question 18:

A PWM signal has a frequency of 16KHz. The minimum increment for the high pulse duration is 500ns. What is the minimum increment in terms of duty cycle (Percentages)?
A) 2%
B) 1%
C) 0.8%
D) 1.6%

Answer 1

Answer: C) 0.8%

Step-by-step explanation:

To find the minimum increment in the duty cycle, we need to first find the period of the PWM signal. The period is the time it takes for the signal to complete one cycle, and it is equal to the reciprocal of the frequency. Thus, the period of the PWM signal is:

Period = 1 / frequency = 1 / 16KHz = 62.5us

Next, we need to find the minimum increment for the high pulse duration. This is given as 500ns. To convert this to a percentage of the period, we can divide it by the period and multiply by 100:

Minimum increment in pulse duration = (500ns / 62.5us) * 100% = 0.8%

Thus, the minimum increment in terms of duty cycle is 0.8%, which is option C).