Question

100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

Answer 1

∠ G = 73° , ∠ H = 98°

Explanation:

EFGH is a cyclic quadrilateral, its 4 vertices lie on the circle.

the opposite angles sum to 180°

A

∠ E + ∠ G = 180° , that is

11x + 8 + 8x + 1 = 180

19x + 9 = 180 ( subtract 9 from both sides )

19x = 171 ( divide both sides by 19 )

x = 9

Then

∠ G = 8x + 1 = 8(9) + 1 = 72 + 1 = 73°

B

∠ H + ∠ F = 180° , that is

6y - 4 + 5y - 3 = 180

11y - 7 = 180 ( add 7 to both sides )

11y = 187 ( divide both sides by 11 )

y = 17

Then

∠ H = 6y - 4 = 6(17) - 4 = 102 - 4 = 98°

Answer 2

A) m∠G = 73°

B) m∠H = 98°

Explanation:

The diagram shows a cyclic quadrilateral.

A cyclic quadrilateral is a four-sided shape drawn inside a circle, where every vertex touches the circle's circumference.

As the opposite angles in a cyclic quadrilateral add up to 180°, then:

• m∠E + m∠G = 180°
• m∠H + m∠F = 180°

We can use these equations to find the values of x and y.

m∠E + m∠G = 180°

(11x + 8)° + (8x + 1)° = 180°

11x + 8 + 8x + 1 = 180

19x + 9 = 180

19x + 9 - 9 = 180 - 9

19x = 171

19x ÷ 19 = 171 ÷ 19

x = 9

m∠H + m∠F = 180°

(6y - 4)° + (5y - 3)° = 180°

6y - 4 + 5y - 3 = 180

11y - 7 = 180

11y - 7 + 7 = 180 + 7

11y = 187

11y ÷ 11 = 187 ÷ 11

y = 17

Now we have found the values of x and y, substitute them back into the angle expressions to find m∠G and m∠H.

m∠G = (8x + 1)°

m∠G = (8(9) + 1)°

m∠G = (72 + 1)°

m∠G = 73°

m∠H = (6y - 4)°

m∠H = (6(17) - 4)°

m∠H = (102 - 4)°

m∠H = 98°