Answer:
53 (seconds)
Explanation:
Let's calculate each of the boy's time to reach the destination and subtract them from each other to get our answer.
Bill:
Using the Pythagorean Theorem, a^2 + b^2 = c^2
Plugging in:
300^2 + (500+150)^2 = c^2
90000 + 650^2 = c^2 (you're gonna want a calculator)
90000 + 422500 = c^2
512500= c^2
Take the square root of both sides, isolating the variable c:
c= 715.891053 m
round it off: 716 m
c stands for the distance that Bill has to walk. If he is walking at 3 meters per second, we can divide to get the number of seconds:
716 / 3 = 238.666667 seconds to get to the playground
round it off: 239
Ted:
Using the Pythagorean Theorem, a^2 + b^2 = c^2
Plugging in:
300^2 + 500^2 = c^2
90000 + 250000 = c^2
340000=c^2
Take the square root of both sides, isolating the variable c:
c= 583.095189 m
round it off: 583 m
c stands for the distance that Ted has to walk. If he is walking at 2 meters per second, we can divide to get the number of seconds:
583 / 2 = 291.5 seconds to get to the playground
round it off: 292
Lastly, subtract the number of seconds it took Ted to the number of seconds it took Bill because Ted took a longer amount of time, and that will be your answer:
292-239= 53
The shorter route 53 seconds faster