Answer:
Explanation:
displacement is integral from t = 0 to 5 of vdt or (3t - 8) dt which you can work out.
distance is the integral from 0 to 5 of |v| dt. Easiest way to do this is to break up the integral into + and - parts and make the integrals positive. The zero for v is at 8/3 s, so
distance is the integral from t = 0 to 8/3 of -(3t-8)dt + integral from 8/3 to 5 of (3t -8)dt
Enjoy!