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If x=15-root 2 find the value of x²-5x+3​

User SurfeurX
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To find the value of x²-5x+3 when x=15-√2, we substitute the value of x into the expression:

x² - 5x + 3 = (15-√2)² - 5(15-√2) + 3

First, let's expand (15-√2)² using the formula for the square of a binomial:

(15-√2)² = (15)² - 2(15)(√2) + (√2)²

= 225 - 30√2 + 2

Simplifying further:

(15-√2)² = 227 - 30√2

Now we substitute this back into the expression:

x² - 5x + 3 = 227 - 30√2 - 5(15-√2) + 3

= 227 - 30√2 - 75 + 5√2 + 3

= 155 - 25√2

Therefore, the value of x²-5x+3 when x=15-√2 is 155 - 25√2.

User CSturgess
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