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Removing the head and the tail nodes of a LinkedList frees up all memory taken up by the LinkedList given that the LinkedList has more than 2 nodes. TRUE FALSE

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The statement "Removing the head and the tail nodes of a LinkedList frees up all memory taken up by the LinkedList given that the LinkedList has more than 2 nodes" is false. Explanation:Linked lists are one of the most basic data structures that exist. They are commonly used to store collections of data that can be expanded or contracted over time. A linked list is made up of nodes that contain a value and a reference to the next node in the list. The first node in the list is called the head, while the last node is called the tail. There are several ways to remove a node from a linked list. The process will vary depending on the type of linked list and the specific implementation. If the linked list has only one node, then removing the head node or the tail node would result in an empty linked list. This means that all memory taken up by the linked list will be freed up. However, if the linked list has more than two nodes, removing the head node or the tail node will only remove one node from the list. The rest of the nodes in the linked list will still be allocated in memory. Therefore, removing the head and the tail nodes of a LinkedList does not free up all memory taken up by the LinkedList given that the LinkedList has more than 2 nodes.

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