Answer:
the final velocity is 8m/s and distance covered by the vehicle within the 10s is 40m.
Step-by-step explanation:
using the equations of motion.
The final velocity can be calculated using the equation:
v = u + at
where:
v = final velocity
u = initial velocity (since the vehicle starts from rest, the initial velocity u is 0)
a = acceleration
t = time
Given:
a = 0.8 m/s^2 (acceleration)
t = 10 s (time)
Plugging in the values, we have:
v = 0 + (0.8 ) * 10
v = 8 m/s
So, the final velocity of the vehicle after 10 seconds is 8 m/s.
2. Distance covered (s):
The distance covered can be calculated using the equation:
s = ut + (1/2)at^2
where:
s = distance covered
u = initial velocity
a = acceleration
t = time
Given:
u = 0 m/s (initial velocity)
a = 0.8 m/s^2 (acceleration)
t = 10 s (time)
Plugging in the values, we have:
s = (0 ) * 10 + (1/2)(0.8 )(10 )^2
s = 0 + (1/2)(0.8 )(100 )c
s = 40 m
So, the vehicle covers a distance of 40 meters within the given 10 seconds.