Final answer:
The speed of the generator for giving 240V on open circuit is approximately 50.54 rpm. The rated output of the machine is 440 kW.
Step-by-step explanation:
To calculate the speed of the generator for giving 240V on open circuit, we can use the formula:
V = 4.44 * N * B * Z * A
Where:
- V is the voltage in volts (240V in this case)
- N is the speed of the generator in rpm
- B is the flux per pole in Weber (0.05 Wb in this case)
- Z is the number of conductors in parallel between brushes (4 in this case)
- A is the number of parallel paths in the armature (120 slots in this case)
We can rearrange the formula to solve for N:
N = V / (4.44 * B * Z * A)
Substituting the given values:
N = 240 / (4.44 * 0.05 * 4 * 120) = 50.54 rpm
Therefore, the speed of the generator for giving 240V on open circuit is approximately 50.54 rpm.
Now, to find the rated output of the machine when the voltage drops to 220V on full load:
We can use the formula:
P = V * I
Where:
- P is the power in watts (rated output in this case)
- V is the voltage in volts (220V in this case)
- I is the current in amperes (to be determined)
We can rearrange the formula to solve for I:
I = P / V
Substituting the given values:
I = 440,000 / 220 = 2000 A
Therefore, the rated output of the machine is 440 kW.