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The volume of 0.0315 mol of a gas at 828 mmHg and 26.8 is C is ?
mL

1 Answer

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To determine the volume of a gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = Pressure (in atmospheres)
V = Volume (in liters)
n = Number of moles
R = Ideal gas constant (0.0821 L·atm/(mol·K))
T = Temperature (in Kelvin)

First, let's convert the given pressure from mmHg to atm:

1 atm = 760 mmHg

So, the pressure is 828 mmHg * (1 atm / 760 mmHg) = 1.0895 atm.

Now, we need to convert the given temperature from degrees Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 26.8 °C + 273.15 = 299.95 K.

Next, let's substitute the known values into the ideal gas law equation:

V = (nRT) / P

V = (0.0315 mol * 0.0821 L·atm/(mol·K) * 299.95 K) / 1.0895 atm

V = 0.7509 L

Finally, let's convert the volume from liters to milliliters:

V(mL) = V(L) * 1000

V(mL) = 0.7509 L * 1000 = 750.9 mL

Therefore, the volume of 0.0315 mol of the gas at 828 mmHg and 26.8 °C is approximately 750.9 mL
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