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If Ted's weight increased by 36 percent and Jessica's weight decreased by 22 percent during a certain year, the ratio of Ted's weight to Jessica's weight at the end of the year was how many times the ratio at the beginning of the year?

User Akasha
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Answer: 1.74

Step-by-step explanation:

Let's assume Ted's initial weight is T and Jessica's initial weight is J.

Given that Ted's weight increased by 36% and Jessica's weight decreased by 22% during a certain year.

Ted's weight at the end of the year will be (T+36% of T) = (T + 0.36T) = 1.36T

Jessica's weight at the end of the year will be (J-22% of J) = (J - 0.22J) = 0.78J

The ratio of Ted's weight to Jessica's weight at the beginning of the year is T/J

The ratio of Ted's weight to Jessica's weight at the end of the year is 1.36T/0.78J

Now, we need to find the ratio of (1.36T/0.78J) to (T/J)

= (1.36/0.78) = 1.74

Therefore, the ratio of Ted's weight to Jessica's weight at the end of the year was 1.74 times the ratio at the beginning of the year.

Hence, the answer is 1.74.

User Merari
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