Question

Two regular polygons P and Q are such that the number of sides of P is twice the number of sides of Q, the difference between the exterior angles of P and Q is 45°, find the number of sides of P?​

Answer 1

Explanation:

Exterior angles sum to 360 degrees Q = 2P For the number of sides

360 / P = 360/ (2P ) + 45

720 = 360 + 90 P

360 = 90P

P = 4 sides THEN Q = 8 SIDES