Question

A hiker begins a trip by first walking 22. 5 km southeast from her base camp. On the second day she walks 45. 0 km in a direction 60. 0° north of east, at which point she discovers a forest ranger's tower. (a) Determine the components of the hiker's displacements in the first and second days. Ax =

15. 9

Correct: Your answer is correct. Km
Ay =
-15. 9

Correct: Your answer is correct. Km
Bx = 22. 5 km
By = 39 km

(b) Determine the components of the hiker's total displacement for the trip. Rx = 38. 4 km
Ry = __km

(c) Find the magnitude and direction of the displacement from base camp. Magnitude___ km
Direction ___° north of east

Answer 1

ΣAx = 15.9 + 39 = 54.9 km total X displacement

ΣAy = -15.9 + 22.5 = 6.6 km total Y displacement

(54.9^2 + 6.6^2)^1/2 = 55.3 km total displacement for trip

6.6 / 54.9 = .12 = tan 6.9 deg North of East

(Find total X - components and total Y components which gives the X and Y components of the final vector)