Question

Find three consecutive even integers such that the product of the first and the second is 8

greater than - 10 times the third integer.

Answer 1

-4, -2, 0 or -8, -6, -4

Explanation:

#1 =x

#2 = x+2

#3 = x+4

x(x+2) = -10(x+4) + 8

x^2 + 2x = -10x - 40 + 8

x^2 + 12x + 32 = 0

(x+8)(x+4) = 0

x = -8 or x = -4 so:

#1 = -8 or -4

#2 = -6 or -2

#3 = -4 or 0