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Find the critical numbers of f(x)=x3+3x2+3x−6.

User Fritz
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1 Answer

2 votes

Answer:

x = -1

Explanation:


f(x)=x^3+3x^2+3x-6\\f'(x)=3x^2+6x+3\\\\0=3x^2+6x+3\\0=x^2+2x+1\\0=(x+1)^2\\0=x+1\\x=-1

Therefore, the only critical number of f(x) is x=-1

User Fazlul
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