99,028 views
39 votes
39 votes
The sodium (Na) content of 1 particular can of soup is 890 mg sodium in 1 c. What is the molarity of sodium (Na) in the soup? (Note: 4 c = 1 qt, and 1 qt = 0.946 L.) (3 points)

User Majid Yaghouti
by
2.7k points

1 Answer

10 votes
10 votes
To find the molarity of sodium in the soup, we need to first convert the mass of sodium in the soup to moles. The atomic weight of sodium is 22.99 g/mol, so we can use the following conversion to find the number of moles of sodium in the soup:

moles Na = (890 mg Na) / (22.99 g/mol) = 38.8 moles Na

Next, we need to find the volume of the soup in liters. Since 4 cups is equal to 1 quart and 1 quart is equal to 0.946 liters, we can convert the volume of the soup from cups to liters using the following conversion:

volume (L) = (1 c) * (4 c/1 qt) * (0.946 L/1 qt) = 3.784 L

Finally, we can use the number of moles of sodium and the volume of the soup to calculate the molarity of sodium in the soup using the following formula:

molarity = (moles Na) / (volume (L)) = 38.8 moles Na / 3.784 L = 10.3 M

Therefore, the molarity of sodium in the soup is approximately 10.3 M.
User Roberg
by
2.8k points