Question

The sodium (Na) content of 1 particular can of soup is 890 mg sodium in 1 c. What is the molarity of sodium (Na) in the soup? (Note: 4 c = 1 qt, and 1 qt = 0.946 L.) (3 points)

Answer 1

0.164 M

Step-by-step explanation:

Molarity is defined as moles of solute per liter of solution. In order to arrive at the desired units, dimensional analysis must be performed.

To find moles of sodium:

`890\ mg\ Na((1\ g)/(1000\ mg))((1\ mol\ Na)/(22.99\ g\ Na))=0.0387\ mol\ Na`

To find liters of solution:

`1\ cup((1\ qt)/(4\ cups))((0.946\ L)/(1\ qt))=0.2365\ L`

The ratio of sodium to solution can then be written as
`(0.0387\ mol)/(0.2365\ L)`. This can be simplified by dividing the numbers,
`0.164(mol)/(L)` or 0.164 M.