Question

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81. III A flat, circular disk of radius R is uniformly charged with CALC total charge Q. The disk spins at angular velocity o about an axis through its center. What is the magnetic field strength at t

Answer 1

This Physics problem involves calculating the magnetic field at a point on the axis of a uniformly charged, spinning disk using the Biot-Savart Law.

Step-by-step explanation:

The question is related to the magnetic field produced by a spinning charged disk in Physics. To find the magnetic field at a point on the axis of the disk, we use the Biot-Savart Law, which relates a current element to the magnetic field it produces at a certain point in space. For a spinning disk with charge density σ and angular velocity ω, we can consider each infinitesimal charge element as a small current loop. The integration of these infinitesimal magnetic fields due to each current element gives us the magnetic field at a point on the axis.

In the specific case provided with σ = 1C/m², R = 0.2 m, h = 0.02 m, and ω = 400 rad/sec, we would need to perform the integration to get the magnetic field value. We would then compare this with the Earth's magnetic field of 0.00005 T or 1/2 Gauss for context.

Answer 2

The magnetic field at a point on the axis of a uniformly charged spinning disk can be calculated using the formula: B = (u₀ * Q * R² * w)/(4 * pi * h³).

Step-by-step explanation:

The magnetic field at a point on the axis of a uniformly charged spinning disk can be calculated using the formula:

B = (u₀ * Q * R² * w)/(4 * pi * h³)

Where B is the magnetic field, u₀ is the magnetic constant, Q is the total charge on the disk, R is the radius of the disk, w is the angular velocity of the disk, and h is the distance from the center of the disk to the point on the axis.