Final answer:
Rolle's Theorem can be applied to f(x) = cos x on the closed interval [π, 3π]. Values of c in the open interval (a, b) such that f'(c) = 0 are x = nπ, where n is an integer.
Step-by-step explanation:
According to Rolle's Theorem, for a function to satisfy the conditions required for the theorem to be applicable on the closed interval [a, b], three conditions must be met:
- The function must be continuous on the closed interval [a, b].
- The function must be differentiable on the open interval (a, b).
- The function must have the same value at the endpoints, meaning f(a) = f(b).
For the given function f(x) = cos x on the closed interval [π, 3π], all three conditions are satisfied. Therefore, Rolle's Theorem can be applied.
To find all values of c in the open interval (a, b) such that f'(c) = 0, we need to find where the derivative of cos x equals zero. Since the derivative of cos x is -sin x, setting -sin x = 0 gives us sin x = 0, and the solutions are x = nπ, where n is an integer.